Step 1
Consider all options
[tex]\begin{gathered} \sqrt[]{2}+\sqrt[]{2}=\text{ 2}\sqrt[]{2}\text{ and 2}\sqrt[]{2\text{ }}is\text{ irrationl} \\ 5\times\sqrt[]{5}=\text{ 5}\sqrt[]{5}\text{ and 5}\sqrt[]{5\text{ }}is\text{ irrational} \end{gathered}[/tex][tex]\begin{gathered} 3\sqrt[]{2\text{ }}+\text{ 2}\sqrt[]{3}=\text{ 3}\sqrt[]{2\text{ }}_{_{_{_{_{_{_{_{_{_{_{}}}}}}}}}}}+2\sqrt[]{3}\text{ and this is irrational} \\ \sqrt[]{2}\times\sqrt[]{18}=\sqrt[]{36\text{ }}=6\text{ and 6 is rational} \end{gathered}[/tex]Hence the answer is option A
