im trying to see if what i think the answer is is correct for the width i got 2x^2+1

Given the expression:
[tex]10x^2+5x[/tex]we already know that 5x is a common factor, then, if we divide each term by 5x we get:
[tex]\begin{gathered} \frac{10x^2}{5x}=2x \\ \frac{5x}{5x}=1 \end{gathered}[/tex]then, we can factor the expression like this:
[tex]10x^2+5x=5x(2x+1)[/tex]therefore, the width of Heng's area model is 2x+1