Given the system of equations:
x - 3y = 4
2x - 6y = Q
Let's find the value of Q.
Let's solve the equations simulateneously using substitution method.
Rewrite the first equation for x:
• Add 3y to both sides of equation 1
x - 3y + 3y = 4 + 3y
x = 4 + 3y
• Substitute (4 + 3y) for x in equation 2:
2x - 6y = Q
2(4 + 3y) - 6y = Q
• Apply distributive property:
2(4) + 2(3y) - 6y = Q
8 + 6y - 6y = Q
8 + 0 = Q
8 = Q
Q = 8
Therefore, the value of Q is 8
ANSWER:
8
