Respuesta :

Here, we want to graph the given line

Firstly, we write the equation in the standard form

The standard form is;

[tex]y\text{ = mx + b}[/tex]

where m represents the slope and b is the y-intercept

We have this as;

[tex]\begin{gathered} 5y\text{ = 9x + 45} \\ \text{divide through by 5} \\ y\text{ = }\frac{9}{5}x\text{ + }\frac{45}{5} \\ \\ y\text{ = 1.8x + 9} \end{gathered}[/tex]

we have the y-intercept, this is 9, so we mark the point (0,9)

What is left is to get the possible x-intercept

As the value of y at this point is zero

We have it that;

[tex]\begin{gathered} 0\text{ = 1.8x + 9} \\ 1.8x\text{ = -9} \\ x\text{ = }\frac{-9}{1.8} \\ x\text{ = -5} \end{gathered}[/tex]

The x-intercept is -5, which in the coordinate form is (-5,0)

So, by joining the points (-5,0) and (0,9), we have the graph of the line

A plot is shown below;

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