Question

23=1/3b-2+4/3bwhat is the value of b?

Answer 1

$23\text{ = }\frac{1}{3b}-2+\text{ }\frac{4}{3b}$

Next, we multiply throughout by the L.C.M of the denominators ( 3b)

$23\text{ ( 3b ) = ( 3b ) }\frac{1}{3b\text{ }}\text{ - 2 ( 3b ) + }\frac{4\text{ ( 3b )}}{3b}$$\begin{gathered} 69b\text{ = 1 - 6b + 4 } \\ 69b\text{ + 6b = 5} \\ 75b\text{ = 5} \\ b\text{ = }\frac{5}{75}\text{ = }\frac{1}{15} \end{gathered}$

Thus the value of b is

$\frac{1}{15}$