Question

write an expression that is equivalent to each original expression use expressions in the box below not all Expressions will be used

Answer 1

The first expression is

$(7\times6)+(7\times y)$

since there is 7 in both parenthesis, we can factorize 7, then we can write

$(7\times6)+(7\times y)=7(6+y)$

Second expression.

In this part, we have

$y(6+7)$

by applying the distributive law, this expression is equivalent to

$y(6+7)=y\times6+y\times7$

Third expression.

We have in this part:

$(6\times y)+(6\times7)$

similarly to the first question, we can factorize 6, then we obtain

$(6\times y)+(6\times7)=6(y+7)$

Fourth expression.

We have in this part:

$y(6+y)$

by applying the distributive law, this expression is equivalent to

$\begin{gathered} y(6+y)=y\times6+y\times y \\ \sin ce\text{ y times y is } \\ y^2 \\ \text{then we have} \\ y(6+y)=y\times6+y^2 \end{gathered}$