Respuesta :

Given:

[tex]\frac{(x-3)(x+2)}{(x+1)(x-3)}[/tex]

Find-:

State any restriction on the variable

Explanation-:

Simplify the expression

[tex]\begin{gathered} =\frac{(x-3)(x+2)}{(x+1)(x-3)} \\ \\ =\frac{x+2}{x+1} \end{gathered}[/tex]

Denominal is not equal to zero then

[tex]\begin{gathered} x+1\ne0 \\ \\ x\ne-1 \end{gathered}[/tex]

So the function restricts at x=1.

Relax