Question

The specific heat of a certain type of cooking is 1.75 J(g ⋅ °C). How much heat energy is needed to raise the temperature of 2.44 kg of this oil from 23 °C to 191 °C? q = ___________ J

Answer 1

The heat abvsorved by a substance is calculated according to the following equation:

$q=m\times C\times\Delta T$

Where q is the heat, m is the mass of the substance, C is the specific heat and AT is the temperature increment. Therefore we have all the required data to solve this problem:

$q=2440\text{ g }\times1.75\frac{J}{g\cdot\degree C}\times(191\degree C-23\degree C)=717360\text{ J}$

Just be sure all quantities are in the corresponding units