Identify two similar triangles in the figure below, and complete the explanation of why they are similar. Then find AB. B А C 21 D ZA = (select) and ZABD = (select), so ABD - ACB by the (select)y Triangle Similarity Theorem. AB =

Identify two similar triangles in the figure below and complete the explanation of why they are similar Then find AB B А C 21 D ZA select and ZABD select so ABD class=

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Answer:

∠A ≅ ∠A and ∠ABD ≅ ∠ACB, so ΔABD ≅ ΔACB by the AA (Angle - Angle) Triangle Similarity Theorem.

AB = 10

Explanation:

An angle is congruent to itself, so ∠A ≅ ∠A

On the other hand, taking into account the representation of the angles, we can say that: ∠ABD ≅ ∠ACB

Then, the triangles ABD and ACB are congruent by the AA (Angle-Angle) triangle similarity theorem because we have two congruent angles:

∠A ≅ ∠A

∠ABD ≅ ∠ACB

Now, if two triangles are similar their corresponding sides are proportional.

So, we can formulate the following equation:

[tex]\frac{AB}{AC}=\frac{AD}{AB}[/tex]

Then, replacing AC by (21 + 4), AD by 4, and solving for AB, we get:

[tex]\begin{gathered} \frac{AB}{21+4}=\frac{4}{AB} \\ AB\times AB=4(21+4) \\ AB^2=4(25) \\ AB^2=100 \\ AB=\sqrt[]{100} \\ AB=10 \end{gathered}[/tex]

Therefore, the answers are:

∠A ≅ ∠A and ∠ABD ≅ ∠ACB, so ΔABD ≅ ΔACB by the AA (Angle - Angle) Triangle Similarity Theorem.

AB = 10

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