The probability of choosing a coin that is worth at leas 10 cents is:
[tex]P=\frac{22}{40}=\frac{11}{20}[/tex]then the probability of obtaining a penny is:
[tex]P=\frac{8}{39}[/tex]Then the probability to obtain a coin of at least 10 cents and then a penny is:
[tex]P=\frac{11}{20}\cdot\frac{8}{39}=\frac{22}{195}[/tex]