Given:
The amount of ice is,
[tex]m=1\text{ g}[/tex]To find:
The amount of heat is required to change 1 gram of ice at 0°C to liquid water at 0°C
Explanation:
The latent heat for melting of ice is,
[tex]L=80\text{ cal/g}[/tex]The amount of heat for the ice to melt is and become water at
[tex]0\text{ }\degree C[/tex]is,
[tex]\begin{gathered} H=mL \\ =1\times80 \\ =80\text{ cal} \end{gathered}[/tex]Hence, the amount of heat is 80 cal.