Question

(23) Set up the system of equations:The cost of 3 apples and 7 tangerines is $2.10. Four apples and 3 tangerines cost $1.85.up the system of equations to find the cost of each apple and tangerine. 3A +7T - 2.104A - 3T - 1.853A + 7T + 2.104A + 3T + 1853A + 7T - 2.104A + 3T = 1.853(A+T) - 2.104A+T) - 1.85

Answer 1

We have to write the system of equations.

The cost of 3 apples and 7 tangerines is $2.10.

If A is the price of the apples and T is the price of the tangerine, we can write:

$3A+7T=2.10$

We also know that 4 apples and 3 tangerines cost $1.85, so we can write:

$4A+3T=1.85$

The system of equations is then:

$\begin{cases}3A+7T=2.10 \\ 4A+3T=1.85\end{cases}$

Answer: The equations of the system are 3A + 7T = 2.10 and 4A + 3T = 1.85.