Recall that given two points, the midpoint of a line segment is determined by the formula
[tex]\begin{gathered} M=\mleft(\dfrac{x_1 + x_2}{2},\; \dfrac{y_1 + y_2}{2}\mright) \\ \text{where} \\ (x_1,y_1)\text{ and }(x_2,y_2)\text{ are the two endpoints of the line segment} \end{gathered}[/tex]Substitute the following and we get
[tex]\begin{gathered} (x_1,y_1)=(6,3) \\ (x_2,y_2)=(-6,-1) \\ \\ M=\mleft(\dfrac{x_1 + x_2}{2},\; \dfrac{y_1 + y_2}{2}\mright) \\ M=\mleft(\dfrac{6 + -6}{2},\; \dfrac{3 + -1}{2}\mright) \\ M=\mleft(\dfrac{0}{2},\; \dfrac{2}{2}\mright) \\ M=(0,\; 1) \end{gathered}[/tex]Therefore, the midpoint of line segment is (0,1)
