Calculate an estimate for the maximum number of drinks a 110lb female can consume without going over 0.08 BAC if she plans on leaving the party in 2 hours.

Respuesta :

we have the following:

The formula is:

[tex]B=-0.015\cdot t+\frac{2.84\cdot N}{W\cdot g}[/tex]

replacing,

where

B is blood alcohol content

t is the time

N is the maximum number of drinks

W is the weight

and g a gender constant (0.55 for wormen)

[tex]\begin{gathered} 0.08=-0.015\cdot2+\frac{2.84\cdot N}{110\cdot0.55} \\ \\ 0.08=-0.03+0.0469N \\ N=\frac{0.08+0.03}{0.0469} \\ N=2.34\cong2 \end{gathered}[/tex]

therefor,e th

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