enter a number into each box to create an equation that has exactly one real solution?3(8x+6)-x=[]x+[]

Let's expand the left-hand side of the equation:
[tex]\begin{gathered} 3(8x+6)-x \\ =24x+18-x \\ =23x+18 \end{gathered}[/tex]The right hand side is
___x + ___
We can put any number except "23" and "18" in the respective boxes for the algebraic equation to have one solution.
Let's put
___x + ___
2x + 10
So, first blank is "2" and second blank is "10".