Question

Write the expression with a single base and single positive exponent then simplify. y^{-4}(y^2)^2 The base is AnswerThe exponent is AnswerThis simplifies to Answer

Answer 1

The expression is given as,

$y^{-4}\cdot(y^2)^2$

Consider the following laws of exponents,

$\begin{gathered} (x^m)^n=x^{mn} \\ x^m\cdot x^n=x^{m+n} \end{gathered}$

Use the above laws to simplify the expression as follows,

$\begin{gathered} =y^{-4}\cdot(y^{2\cdot2}) \\ =y^{-4}\cdot(y^4) \\ =y^{-4+4} \\ =y^0 \\ =1 \end{gathered}$

The value 1 can be expressed as,

$=1^1$

Therefore, the base is 1, and the exponent is also 1.