We have the following:
[tex]k\cdot\mleft(5n+4\mright)=h+20n[/tex]What we have to do is replace each answer option and the one that is exactly the same on both sides is the correct answer
[tex]\begin{gathered} k=4,h=16 \\ 4\cdot(5n+4)=16+20n \\ 20n+16=16+20n \\ \text{TRUE} \\ \\ k=9,h=7 \\ 9\cdot(5n+4)=7+20n \\ 45n+36=7+20n \\ \text{FALSE} \\ \\ k=2,h=6 \\ 2\cdot(5n+4)=6+20n \\ 10n+8=6+20n \\ \text{FALSE} \\ \\ k=4,h=8 \\ 4\cdot(5n+4)=8+20n \\ 20n+16=8+20n \\ \text{FALSE} \end{gathered}[/tex]Therefore, the correct option is the first k = 4 and h = 16