They would not earn money when the function is equal or less to 0
then we equal 0
[tex](x-3)(450-3x)\leq0\text{ }[/tex]we will have two answers when clear x
[tex]\begin{gathered} (x_1-3)\leq0 \\ x_1\leq3 \\ (450-3x_2)\text{ }\leq\text{0} \\ 450\leq3x_2 \\ x_2\ge\frac{450}{3} \\ x_2\ge150 \end{gathered}[/tex]they won't make money when the ticket price is equal or less than 3 or when the ticket price is equal or greater than 150
the correct expression for not making money is :
[tex](-\infty,3\rbrack\text{ }\lbrack150,\infty)[/tex]