Question

Let O be an angle in quadrant II such that csc =4"Find the exact values of tan 0 and cos 0.

Answer 1

$\begin{gathered} \csc (\theta)=\frac{hypotenuse}{opposite}=\frac{9}{4} \\ \end{gathered}$

The tangent function is given by:

$\tan (\theta)=\frac{opposite}{adjacent}=-\frac{4}{\sqrt[]{65}}$

And the cosine function is:

$\cos (\theta)=\frac{adjacent}{hypotenuse}=-\frac{\sqrt[]{65}}{9}$