Question

I just need to know the equations for both of these-From what height would a compact car have to be dropped to have the same kinetic energy that it was when being driven at 30 m/s?-B) write an equation and answer what height the car would have to be dropped from.

Answer 1

Given data

*The given speed of the compact car is v = 30 m/s

*The value of the acceleration due to gravity is g = 9.8 m/s^2

The expression for the height of the car is given by the conservation of energy as

$\begin{gathered} U_p=U_k \\ mgh=\frac{1}{2}mv^2 \\ h=\frac{v^2}{2g} \end{gathered}$

Substitute the known values in the above expression as

$\begin{gathered} h=\frac{(30)^2}{2\times9.8} \\ =45.91\text{ m} \end{gathered}$

Hence, the height of the car would have to be dropped them is h = 45.91 m