Find the area of the region bounded by the graphs of the following equations.y=5x+6,y=0,x=3andx=8.

Given the equations
y=5x+6,
y=0,
x=3and
x=8
we can build the region
the area is given by the defined integral
[tex]\int _3^8\:5x+6[/tex][tex]\frac{5x^2}{2}+6x|^8_{3^}[/tex][tex]\frac{5(8)^2}{2}+6(8)-\frac{5(3)^2}{2}-6(3)[/tex][tex]167.5[/tex]Area= 167.5 units^2