Respuesta :

Answer:

[tex]log_3729=6[/tex]

Explanations:

Given logarithmic function as shown:

[tex]log_3729[/tex]

This can also be written as:

[tex]log_33^6[/tex]

Carrying the exponent to the back of log will give:

[tex]\begin{gathered} 6log_33 \\ Since\text{ }log_33=1,\text{ }hence; \\ 6log_33=6(1)=6 \end{gathered}[/tex]

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