The given equations are:
[tex]\begin{gathered} y=-2x+1 \\ 3x-2y=5 \end{gathered}[/tex]So from the first equation, we have the value for y. Now we can substitute that value in the second equation for y. We have,
[tex]\begin{gathered} 3x-2(-2x+1)=5 \\ 3x+4x-2=5 \\ 7x=5+2 \\ 7x=7 \\ x=\frac{7}{7}=1 \end{gathered}[/tex]Now we can substitute the value of x in the equation for y,
[tex]y=-2\times1+1=-2+1=-1[/tex]Hence, x = 1 and y = -1.