The information given states the following;
[tex]\begin{gathered} \text{Granny Smith}=4 \\ \text{Honey Crisp}=2 \\ \text{Gala}=3 \\ \text{Fuji}=1 \\ \text{Total}=10 \end{gathered}[/tex]The total number of apples is 10.
Hence, for the experiments, we would have;
[tex]\begin{gathered} P\lbrack E\rbrack=\frac{Number\text{ of required outcomes}}{Number\text{ of all possible outcomes}} \\ P\lbrack\text{Granny Smith\rbrack}=\frac{4}{10} \\ P\lbrack\text{Granny SSmith\rbrack}=\frac{2}{5} \\ \text{Similarly, after replacing the apple he would have;} \\ P\lbrack\text{Honey Crisp\rbrack}=\frac{2}{10} \\ P\lbrack\text{Honey Crisp\rbrack}=\frac{1}{5} \\ \end{gathered}[/tex]The probability that he would pick a Granny Smith apple, replace it, and then choose a Honey Crisp apple is calculated as follows;
[tex]\begin{gathered} P=P\lbrack granny\text{ smith\rbrack x P\lbrack{}honey crisp\rbrack} \\ P=\frac{2}{5}\times\frac{1}{5} \\ P=\frac{2}{25} \end{gathered}[/tex]ANSWER:
The probability is therefore;
[tex]\frac{2}{25}[/tex]