Squaring both sides of the inequality gives
[tex](\sqrt[]{x})^2<10^2[/tex][tex]x<100[/tex]Since x cannot be less than 0 (there is not square root for negative numbers), the above becomes
[tex]0\le x<100[/tex]Now, from the choices given, the numbers that lie in this interval are 93 and 99; thereofre, the correct choices are
C. 93
F. 99.