Respuesta :

To find g o f(x), we need to replace each x in g(x) for f(x), this is:

[tex]\begin{gathered} g\circ f(x)=g(f(x)) \\ g\circ f(x)=\sqrt[]{-(f(x))-2} \\ g\circ f(x)=\sqrt[]{-(2x-3)-2} \end{gathered}[/tex]

Its domain must contain the numbers that make the function be real. In this case the function can be indefinite when having a negative root, it means that the domain of this function is:

[tex]\lbrack\frac{1}{2},\infty)[/tex]

Do the same procedure to find f o g(x):

[tex]\begin{gathered} f\circ g(x)=f(g(x)) \\ f\circ g(x)=2\cdot(g(x))-3 \\ f\circ g(x)=2\cdot(\sqrt[]{-x-2})-3 \end{gathered}[/tex]

The domain of this function is:

[tex](-\infty,-2\rbrack[/tex]

RELAXING NOICE
Relax