Question

Please help with the question below (please try to answer in max 15 minutes).

Answer 1

The surface area of the figure is given by

$Asquare*eachface$

In this case there are 5 squares blue , 2 green and 2 triangles.

top and bottom squares area are:

$L*L=4*3=12cm^2$

For the lateral faces, the area will be:

$\begin{gathered} L*L=6*3=18cm^2 \\ L*L=6*4=24cm^2 \end{gathered}$

We have 3 lateral faces and the other two on the top and bottom of the square:

$SurfaceAreaSquare=12*2+18+24*2=90cm^2$

And now, we have 2 triangle and two squares in green.

$AreaSquare=L*L=5*3=15cm^2*2=30cm^2$$AreaTriangle2=\frac{b*h}{2}=\frac{6*4}{2}=\frac{24}{2}=12cm^2*2=24cm^2$

The surface area is the sum of the green area+ blue area

$SurfaceAreaTotal=90cm^2+30cm^2+24cm^2=144cm^2$