This is algebra 2, function graphsI’m a little confused with how to start it out. ( I scribbled the black so you won’t get confused with the other problem)

Solution:
The graph shown is a graph of a square root function that has been transformed.
The parent square root function is;
[tex]y=\sqrt[]{x}[/tex]The graph of the parent function is as shown below;
The parent function occurs at;
[tex]\begin{gathered} y=\sqrt[]{x} \\ It\text{ occurs at (0,0)} \end{gathered}[/tex]Comparing the parent function to the images in the question.
The red image originates at,
[tex](-3,-3)[/tex]This shows the parent function is translated 3 units to the left on the x-axis and 3 units down from its original position on the y-axis.
Therefore, the equation of the red image is given below;
[tex]\begin{gathered} y=\sqrt[]{x} \\ \\ \text{The equation of the red image translated from the parent function is;} \\ y=\sqrt[]{x+3}-3 \end{gathered}[/tex]The graph is as shown below;
The green image originates at,
[tex](3,3)[/tex]This shows the parent function is translated 3 units to the right on the x-axis and 3 units up from its original position on the y-axis.
Therefore, the equation of the green image is given below;
[tex]\begin{gathered} y=\sqrt[]{x} \\ \\ \text{The equation of the gr}een\text{ image translated from the parent function is;} \\ y=\sqrt[]{x-3}+3 \end{gathered}[/tex]The graph is as shown below;