[tex]\begin{gathered} F(x)=\frac{9}{5}x+32 \\ \\ C(x)=x-273 \end{gathered}[/tex]
Find F(C(x)): Write F and substitute the x by C(x):
[tex]\begin{gathered} F(C(x))=\frac{9}{5}(C(x))+32 \\ \\ F(C(x))=\frac{9}{5}(x-273)+32 \\ \\ F(C(x))=\frac{9}{5}x-\frac{2457}{5}+32 \\ \\ F(C(x))=\frac{9}{5}x-\frac{2457}{5}+\frac{160}{5} \\ \\ F(C(x))=\frac{9}{5}x-\frac{2297}{5} \\ \\ F(C(x))=\frac{9}{5}x-459\frac{2}{5} \end{gathered}[/tex]
As you write F in terms of C it means that F(C(x)) take a temperature given in degrees Kelvin and converts it to degrees Farenheit.
Answers:
[tex]F(C(x))=(\frac{9}{5})x-459\frac{2}{5}[/tex]
F(C(x)) take a temperature given in degrees Kelvin and converts it to degrees Farenheit