Given the functions:
[tex]\begin{gathered} f(\theta)=\sin \theta \\ g(\theta)=\cos \theta \end{gathered}[/tex]we will find the value of [g(θ)]² when θ = 60
So,
[tex]\lbrack g(\theta)\rbrack^2=(\cos \theta)^2[/tex]Substitute with θ = 60
So,
[tex]\lbrack g(\theta)\rbrack^2=(\cos 60)^2=(\frac{1}{2})^2=\frac{1}{2}\times\frac{1}{2}=\frac{1}{4}[/tex]So, the answer will be option → A. [g(θ)]² = 1/4