Respuesta :

Given the functions:

[tex]\begin{gathered} f(\theta)=\sin \theta \\ g(\theta)=\cos \theta \end{gathered}[/tex]

we will find the value of [g(θ)]² when θ = 60

So,

[tex]\lbrack g(\theta)\rbrack^2=(\cos \theta)^2[/tex]

Substitute with θ = 60

So,

[tex]\lbrack g(\theta)\rbrack^2=(\cos 60)^2=(\frac{1}{2})^2=\frac{1}{2}\times\frac{1}{2}=\frac{1}{4}[/tex]

So, the answer will be option → A. [g(θ)]² = 1/4

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