Question

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Answer 1

We just have to use the following formula

$\sigma=\sqrt[]{n\cdot P\cdot(1-P)}$

Where n = 70 and P = 0.7.

$\begin{gathered} \sigma=\sqrt[2]{70\cdot0.7\cdot(1-0.7)}=\sqrt[]{49(0.3)}=\sqrt[]{14.7} \\ \sigma=3.8 \end{gathered}$

Hence, the standard deviation is 3.8.