We need to find two numbers that meet the following...
[tex]\begin{gathered} x-y=24 \\ x\cdot y=756 \end{gathered}[/tex]first, let's clear x from the first equation
[tex]\begin{gathered} x-y+y=24+y \\ x=24+y \end{gathered}[/tex]Second, substitute the solutions x = 24 + y into xy = 756
[tex]\begin{gathered} xy=756 \\ (24+y)\cdot y=756 \\ 24y+y^2=756 \\ 24y+y^2-756=756-756 \\ y^2+24y-756=0 \end{gathered}[/tex]Now, we need to solve this second grade equation
[tex]\begin{gathered} y_{1,\: 2}=\frac{-24\pm\sqrt{24^2-4\cdot\:1\cdot\left(-756\right)}}{2\cdot\:1} \\ y_{1,\: 2}=\frac{-24\pm\:60}{2\cdot\:1} \end{gathered}[/tex]We will obtain two values for y
[tex]y=18,\: y=-42[/tex]We will only use the positive value
Now, we just have to replace y=18 into x=24+y
[tex]\begin{gathered} x=24+y \\ x=24+18 \\ x=42 \end{gathered}[/tex]In conclusion, the two positive numbers that meet the conditions are:
18 and 42