Question

Find the volume of 0.100 M hydrochloric acid necessary to react completely with 1.51 g Al(OH)3.

Answer 1

The balanced chemical reaction is written as:

3HCl + Al(OH)3 = AlCl3 + 3H2O

We calculate as follows:

1.51 g Al(OH)3 ( 1 mol / 78.01 g ) ( 3 mol HCl / 1 mol Al(OH)3 ) ( 1 L / 0.100 mol HCl ) = 0.581 L of 0.100 M HCl solution is needed

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