The relationship between the speed, wavelength and frequency of light is:
[tex]c\text{ = }\lambda f[/tex]where c is the speed of light
λ is the wavelength
and f is the frequency
From the question:
[tex]f\text{ = }6.15\text{ }\times10^{14}Hz[/tex][tex]c\text{ = 3 }\times10^8\text{ m/s}[/tex][tex]\begin{gathered} c\text{ = }\lambda f \\ \lambda\text{ = }\frac{c}{f} \\ \lambda=\frac{3\times10^8}{6.15\times10^{14}}\text{ } \\ \lambda\text{ = }0.488\times10^{-6} \\ \lambda\text{ = 4.88}\times10^{-1}\times10^{-6} \\ \lambda=4.88\times10^{-7}m\text{ } \end{gathered}[/tex]Therefore, the wavelength of the photon of light is
[tex]4.88\text{ }\times10^{-7}m[/tex]