Explanation:
we can only have a head or a tail when we flip
A dime flipped 4 times, the sample space of that:
HHHH, HHHT, HHTT, HTTT, TTTT, THHH, TTHH, TTTH, THTH, HTHT, HTTH, THHT,
For the total possible outcome of flipping a coin, we use the formula:
2^(number of times dimewas flipped) = 2^4
Total possible outcome = 16
To have atleast 2 heads = HHHH, HHHT, HHTT, THHH, TTHH, THTH, HTHT, HTTH, THHT, HTHH, HHTH = 11
Probability of atleast two heads:
[tex]\begin{gathered} Probability=\text{ 11/ 16} \\ \text{Probability = 0.6875} \end{gathered}[/tex]