We have a compound inequality
[tex]3-x\ge2\text{ or }4x+2\ge10[/tex]
And we must graph its solution.
To graph the solution we need to solve the two inequalities of the compound inequality
1. 3 - x >= 2
To solve it we must:
- Subtract 3 from both sides
[tex]\begin{gathered} 3-x-3\ge2-3 \\ \text{ Simplifying,} \\ -x\ge-1 \end{gathered}[/tex]
- Multiply both sides by -1.
We must bear in mind that when we have an inequality and we multiply or divide it by a negative number, the symbols change their meaning.
[tex]\begin{gathered} -x\cdot-1\le-1\cdot-1 \\ \text{ Simplifying, } \\ x\le1 \end{gathered}[/tex]
2. 4x + 2 >= 10
To solve it we must:
- Subtract 2 from both sides
[tex]\begin{gathered} 4x+2-2\ge10-2 \\ \text{ Simplifying,} \\ 4x\ge8 \end{gathered}[/tex]
- Divide both sides by 4
[tex]\begin{gathered} \frac{4x}{4}\ge\frac{8}{4} \\ \text{ Simplifying, } \\ x\ge2 \end{gathered}[/tex]
Finally, since the two inequalities has an 'or' means that the graph will be the graph will be the union of the solutions of each inequality
So, the correct answer is