Given:
[tex]Z^2+112+28=0[/tex]Find value of Z.
Sol:.
[tex]\begin{gathered} Z^2+112+28=0 \\ Z^2+140=0 \\ Z^2=-140 \\ Z=\pm\sqrt[]{-140} \end{gathered}[/tex]So the value of Z is:
[tex]\begin{gathered} Z=\pm11.83i \\ Z=11.83i\text{ and } \\ Z=-11.83i \end{gathered}[/tex]