Question

find the distance between each pair of points in the coordinate plane.(3,1) and (3,-5)

Answer 1

We have the following:

$d(P_1,P_2)=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}$

Now,

$\begin{gathered} P_1=(3,1)=(x_1,y_1) \\ P_2=(3,-5)=(x_2,y_2) \end{gathered}$

replacing:

$\begin{gathered} d=\sqrt[]{x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt[]{(3-3)^2+(-5-1_{})^2} \\ d=\sqrt[]{0^2+(-6)^2} \\ d=\sqrt[]{36} \\ d=6 \end{gathered}$

Therefore, the answer is 6 units