Given data
*The given initial speed of the car is u = 0 m/s
*The given acceleration of the car is a = 1.15 m/s^2
*The given final speed of the car is v = 2.5 m/s
The formula for the distance travelled by the car is given by the kinematic equation of motion as
[tex]\begin{gathered} v^2=u^2+2as \\ s=\frac{v^2-u^2}{2a} \end{gathered}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} s=\frac{(2.5)^2-(0)^2}{2(1.15)} \\ =2.71\text{ m} \end{gathered}[/tex]Hence, the distance travelled by the car is s = 2.71 m
