Respuesta :

[tex]\begin{gathered} x_1=5,y_1=2,x_2=-5,y_2=6 \\ \text{The equation of line,} \\ y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ y-2=\frac{6-2}{-5-5}(x-5) \\ y-2=-\frac{2}{5}(x-5) \\ 5y-10=-2x+10 \\ 5y=-2x+20 \\ y=-\frac{2}{5}x+4 \end{gathered}[/tex]

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