Given:-
[tex]6,8,10,\ldots[/tex]To find:-
The sequence in it.
Since the sequence is 6 for 1st term and 8 for 2nd term and 10 for 3rd term.
So the sequence is,
[tex]2n+4[/tex]The required sequence is 2n+4.
Now when n=1. we have,
[tex]\begin{gathered} 2(1)+4=2+4 \\ \text{ =6} \end{gathered}[/tex]When n=2. we have,
[tex]\begin{gathered} 2(2)+4=4+4 \\ \text{ =8} \end{gathered}[/tex]When n=3. we have,
[tex]\begin{gathered} 2(3)+4=6+4 \\ \text{ =10} \end{gathered}[/tex]So from this we can conform that the sequence is 2n+4.