We can express the volume of a cone with the equation:
[tex]V=\frac{1}{3}A_bh=\frac{1}{3}\pi r^2h[/tex]where Ab is the area of the base, r is the radius of the base and h is the height of the cone.
Then, replacing with r=9.7 ft and h=6 ft, we get:
[tex]\begin{gathered} V=\frac{1}{3}\pi\cdot(9.7ft)^2\cdot(6ft) \\ V=\frac{1}{3}\pi\cdot94.09ft^2\cdot6ft \\ V\approx591.2ft^3 \end{gathered}[/tex]Answer: the volume is 591.2 cubic feet.