Question

A chemist wants to make 4,952 mL of a solution with a concentration of 1.65. Howmany liters of a 11.10 solution should be used to make this solution?

Answer 1

1) List known values

V2: 4952 mL

C2: 1.65

C1: 11.10

V1: ?

2) Set the equation

$C1V1=C2V2$

3) Plug in values en solve for V1.

$(11.10)V1=(1.65)(4952mL)$$V1=\frac{(1.65)(4952mL)}{11.10}=736.11mL$

736.11 mL of solution should be used.