(x - 5)^2 = 81
x^2 - 10x + 25 = 81
x^2 - 10x -56 = 0
The equation of bhaskara is
[tex]x=\frac{-b\text{ }\pm\sqrt[]{b^2-4ac}}{2a}[/tex]
In this case, we have, a = 1, b = -10 and c = -56
Therefore:
[tex]x_+=\frac{10\text{ +}\sqrt[]{100+4\cdot56}}{2}=14_{},x_-=\text{ }\frac{10-\sqrt[]{100+4\cdot56}}{2}=\text{ -4}[/tex]
