[tex]\begin{gathered} y-4=\frac{3}{4}(x+8) \\ y-4=\frac{3}{4}(x)+\frac{3}{4}(8) \\ y-4=\frac{3x}{4}+\frac{24}{4} \\ y-4=\frac{3x}{4}+6 \\ -\frac{3x}{4}+y=6+4 \\ -\frac{3x}{4}+y=10,\text{ Convert }x\text{ to positive by multiplying all terms by -1} \\ \frac{3x}{4}-y=-10,\text{ multiply all terms by 4, to get rid of the fraction} \\ 3x-4y=-40 \\ \text{The standard form is }3x-4y=-40 \end{gathered}[/tex]
