Question

a sample of gas held at constant volume is raised from 34.0 atm to 5.90 atm. if the final temperature of the sample is 340.0 K, what was its initial temperature

Answer 1

Answer

To answer this question we need to use the following equation

P1/T1 = P2/T2

We can rearrange to make T1 subject of the formula as shown

T1 = (P1 x T2)/ P2

= (3.40 x 340)/ 5.90

= 195.9 K