∵ The 2 cell phones are proportional
∴ Their dimensions are proportional
[tex]\frac{l_1}{l_2}=\frac{w_1}{w_2}[/tex]
∵ l1 = 5.4 in and l2 = 6.21
∵ w1 = 2.6 in and w2 = ?
Substitute them in the ratio above
[tex]\frac{5.4}{6.21}=\frac{2.6}{w_2}[/tex]
By using cross multiplication
[tex]\begin{gathered} 5.4\times w_2=6.21\times2.6 \\ 5.4w_2=16.146 \end{gathered}[/tex]
Divide both sides by 5.4
[tex]\begin{gathered} \frac{5.4w_2}{5.4}=\frac{16.146}{5.4} \\ w_2=2.99 \end{gathered}[/tex]
The width of the larger cell phone is 2.99 in
The answer is C