Answer:
• (a)0.25q+0.1d=13.75, q=2d-5
,• (b)d=25
,• (c)q=45
Explanation:
Let the number of quarters in his collection = q
Let the number of dimes in his collection = d
• 1 quarter = $0.25
,• 1 dime =$0.10
The total value of his collection = $13.75.
[tex]0.25q+0.1d=13.75\cdots(1)[/tex]He has five fewer quarters than two times the number of dimes.
[tex]q=2d-5\cdots(2)[/tex]The system of equations that describes the situation is:
[tex]\begin{gathered} 0.25q+0.1d=13.75 \\ q=2d-5 \end{gathered}[/tex]Next, we solve for q and d.
Substitute the second equation into the first.
[tex]\begin{gathered} 0.25q+0.1d=13.75 \\ 0.25(2d-5)+0.1d=13.75 \\ \text{Open the bracket} \\ 0.5d-1.25+0.1d=13.75 \\ \text{Collect like terms} \\ 0.5d+0.1d=13.75+1.25 \\ 0.6d=15 \\ \text{Divide both sides by 0.6} \\ \frac{0.6d}{0.6}=\frac{15}{0.6} \\ d=25 \end{gathered}[/tex]Finally, solve for q.
[tex]\begin{gathered} q=2d-5 \\ q=2(25)-5 \\ q=45 \end{gathered}[/tex]Jackson has 25 dimes and 45 quarters in his collection.