Question

Dave the plumber charges a standard rate of $30 for a project plus $40 per hour. He needs to make at least $1310 per week to cover all of his expenses. Create an inequality that can be used to find the minimum number of hours he will need to work on a single project in one week to meet his goal.

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Plumber:

rate:

$30

$40 per hour

total amount = $1310

inequality:

total hours = ?

Step 02:

x = hour

y = 40 x + 30

40x + 30 ≥ 1310

Step 03:

40x + 30 - 30 ≥ 1310 -30

40x / 40 ≥ 1280 / 40

x ≥ 32

The answer is:

40x + 30 ≥ 1310

He needs to work 32 hours to cover all of his expenses.