Respuesta :

Answer:

(-3,1)

Explanation:

Given the endpoints of a line segment: (-3,4) and (-3,-2)

The midpoint is obtained using the formula below:

[tex]M(x,y)=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})[/tex][tex]\begin{gathered} $\mleft(x_1,y_1\mright)=\mleft(-3,4\mright)$ \\ (x_2,y_2)=\mleft(-3,-2\mright) \end{gathered}[/tex]

Substituting the points into M(x,y), we have:

[tex]\begin{gathered} M(x,y)=(\dfrac{-3+(-3)}{2},\dfrac{4+(-2)}{2}) \\ =(\dfrac{-3-3}{2},\dfrac{4-2}{2}) \\ =(\dfrac{-6}{2},\dfrac{2}{2}) \\ =(-3,1) \end{gathered}[/tex]

The midpoint of the segment is (-3, 1).

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